See supercuspidal on Wiktionary
{ "etymology_templates": [ { "args": { "1": "en", "2": "super", "3": "cuspidal" }, "expansion": "super- + cuspidal", "name": "prefix" } ], "etymology_text": "From super- + cuspidal.", "head_templates": [ { "args": { "1": "-" }, "expansion": "supercuspidal (not comparable)", "name": "en-adj" } ], "lang": "English", "lang_code": "en", "pos": "adj", "senses": [ { "categories": [ { "kind": "other", "name": "English entries with incorrect language header", "parents": [ "Entries with incorrect language header", "Entry maintenance" ], "source": "w" }, { "kind": "other", "name": "English terms prefixed with super-", "parents": [], "source": "w" }, { "kind": "other", "name": "Pages with 1 entry", "parents": [], "source": "w" }, { "kind": "other", "name": "Pages with entries", "parents": [], "source": "w" }, { "kind": "topical", "langcode": "en", "name": "Mathematics", "orig": "en:Mathematics", "parents": [ "Formal sciences", "Sciences", "All topics", "Fundamental" ], "source": "w" } ], "examples": [ { "ref": "2015, Manish Mishra, “A Galois side analogue of a theorem of Bernstein”, in arXiv:", "text": "A theorem of Bernstein states that for any compact open subgroup K of G(k), there are, up to unramified twists, only finitely many K-spherical supercuspidal representations of G(k).", "type": "quote" } ], "glosses": [ "That has a zero Jacquet functor for every proper parabolic subgroup" ], "id": "en-supercuspidal-en-adj-BGJ-1RlY", "links": [ [ "mathematics", "mathematics" ], [ "zero", "zero" ], [ "parabolic", "parabolic" ], [ "subgroup", "subgroup" ] ], "raw_glosses": [ "(mathematics) That has a zero Jacquet functor for every proper parabolic subgroup" ], "tags": [ "not-comparable" ], "topics": [ "mathematics", "sciences" ] } ], "word": "supercuspidal" }
{ "etymology_templates": [ { "args": { "1": "en", "2": "super", "3": "cuspidal" }, "expansion": "super- + cuspidal", "name": "prefix" } ], "etymology_text": "From super- + cuspidal.", "head_templates": [ { "args": { "1": "-" }, "expansion": "supercuspidal (not comparable)", "name": "en-adj" } ], "lang": "English", "lang_code": "en", "pos": "adj", "senses": [ { "categories": [ "English adjectives", "English entries with incorrect language header", "English lemmas", "English terms prefixed with super-", "English terms with quotations", "English uncomparable adjectives", "Pages with 1 entry", "Pages with entries", "en:Mathematics" ], "examples": [ { "ref": "2015, Manish Mishra, “A Galois side analogue of a theorem of Bernstein”, in arXiv:", "text": "A theorem of Bernstein states that for any compact open subgroup K of G(k), there are, up to unramified twists, only finitely many K-spherical supercuspidal representations of G(k).", "type": "quote" } ], "glosses": [ "That has a zero Jacquet functor for every proper parabolic subgroup" ], "links": [ [ "mathematics", "mathematics" ], [ "zero", "zero" ], [ "parabolic", "parabolic" ], [ "subgroup", "subgroup" ] ], "raw_glosses": [ "(mathematics) That has a zero Jacquet functor for every proper parabolic subgroup" ], "tags": [ "not-comparable" ], "topics": [ "mathematics", "sciences" ] } ], "word": "supercuspidal" }
Download raw JSONL data for supercuspidal meaning in All languages combined (1.3kB)
This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2024-12-21 from the enwiktionary dump dated 2024-12-04 using wiktextract (d8cb2f3 and 4e554ae). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
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